This new approximation is vulnerable to the same fate as the a1 / b1 solution it replaced; that’s to say, we can keep incrementing K to conjure as many distinct 2-good pairs as we want. The proof doesn’t guarantee that it’s going to happen on any specific cadence, but it says that it will if we try long enough.
Студенты нашли останки викингов в яме для наказаний14:52
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